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Home/ Questions/Q 8653365
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T14:31:27+00:00 2026-06-12T14:31:27+00:00

In the following example when(myMethod(abc, 123)).thenReturn(456); How does the when() method catch the method

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In the following example

when(myMethod("abc", 123)).thenReturn(456);

How does the when() method catch the method name and arguments without actually invoking myMethod()?

Can I write a method to do the same thing as when() so that I get a method pointer and an array of Objects as arguments to invoke later?

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  1. Editorial Team
    Editorial Team
    2026-06-12T14:31:28+00:00Added an answer on June 12, 2026 at 2:31 pm

    The method myMethod is invoked. But it is being invoked on a mock object — that’s the “trick”.

    Of course you can write code that accepts a “method pointer” (in Java, it would be an object of class Method) and some arguments, and use invoke, but doing so does not actually buy you anything over calling the mock object’s myMethod directly.

    It is more common to see when called as follows:

    MyObject myObject = mock(MyObject.class);
    when(myObject.myMethod("abc", 123)).thenReturn(456);
    

    Try printing (or logging) the expression

    myObject.getClass().getName()
    

    here. You will see that the class of the mock object is not actually MyObject. But it is of a class that has the same interface. The calls on this object update some internal state. This allows Mockito to keep track of how it is used, and allows you to assert various things.

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