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Home/ Questions/Q 8807693
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T02:25:50+00:00 2026-06-14T02:25:50+00:00

In the following function, I try to see if a string s is convertible

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In the following function, I try to see if a string s is convertible to type T by seeing if I can read a type T, and if the input is completely consumed afterwards. I want

template <class T>
bool can_be_converted_to(const std::string& s, T& t) 
{ 
  std::istringstream i(s);
  i>>std::boolalpha;
  i>>t;
  if (i and i.eof())
    return true;
  else
    return false;
}

However, can_be_converted_to<bool>("true") evaluates to false, because i.eof() is false at the end of the function.

This is correct, even though the function has read the entire string, because it hasn’t attempted to read past the end of the string. (So, apparently this function works for int and double because istringstream reads past the end when reading these.)

So, assuming that I should indeed be checking (i and <input completely consumed>):

Q: How do I check that the input was completely consumed w/o using eof()?

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  1. Editorial Team
    Editorial Team
    2026-06-14T02:25:51+00:00Added an answer on June 14, 2026 at 2:25 am

    Use peek() or get() to check what’s next in the stream:

    return (i >> std::boolalpha >> t && i.peek() == EOF);
    

    Your version doesn’t work for integers, either. Consider this input: 123 45. It’ll read 123 and report true, even though there are still some characters left in the stream.

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