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Home/ Questions/Q 739337
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T08:23:20+00:00 2026-05-14T08:23:20+00:00

In the following JavaScript code main() is called. My question is why the second

  • 0

In the following JavaScript code main() is called.
My question is why the second constructor is called rather than the first one ?
What am I missing here ?

Thanks !!

function AllInputs() {
   alert("cons 1");
   this.radioInputs = [];
   alert(this);
}

function AllInputs(radioElement) {
   alert("cons 2");
   this.radioInputs = [radioElement];
   alert(this);
}

AllInputs.prototype.toString = function() {
   return "[object AllInputs: radioInputs: " + this.radioInputs.length + "]";
}

function main() {
   var result = new AllInputs();
}
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  1. Editorial Team
    Editorial Team
    2026-05-14T08:23:20+00:00Added an answer on May 14, 2026 at 8:23 am

    Javascript does not support overloaded functions.

    When you define the same function twice, the second definition replaces the first one.

    Instead, you should make a single function, and check arguments.length to see how many arguments were passed.

    For example:

    function AllInputs(radioElement) {
       this.radioInputs = arguments.length ? [radioElement] : [];
       alert(this);
    }
    
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