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Home/ Questions/Q 627839
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T19:34:17+00:00 2026-05-13T19:34:17+00:00

In the following line Graph<Number,Number> ig = Graphs.<Number,Number>synchronizedDirectedGraph( new DirectedSparseMultigraph<Number,Number>()); could you please explain

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In the following line

Graph<Number,Number> ig = Graphs.<Number,Number>synchronizedDirectedGraph(
                              new DirectedSparseMultigraph<Number,Number>());

could you please explain what Graphs.<Number,Number>synchronizedDirectedGraph means ? It looks like a call to a method Graphs.synchronizedDirectedGraph, but the template-like thingie after the dot puzzles me (at least due to my C++ background).

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  1. Editorial Team
    Editorial Team
    2026-05-13T19:34:17+00:00Added an answer on May 13, 2026 at 7:34 pm

    The problem is that Java is not very intelligent in the places it supports type inference.

    For a method:

    class A{}
    class B extends A{}
    class Y{
      static <T> List<T> x(T t)
    }
    

    It infers the type List<B> from the parameter type B

    List<B> bs = Y.x(new B());
    

    But if you need List<A> you have to cast B or add the compiler hint:

    List<A> as1 = Y.<A> x(new B());
    List<A> as2 = Y.x((A) new B());
    

    Part of the problem is that java generics are invariant so List<B> is not a subtype of List<A>.

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