Question

In the following one to many

CREATE TABLE source(id int, name varchar(10), PRIMARY KEY(id)); CREATE TABLE params(id int, source int, value int); 

where params.source is a foreign key to source.id

INSERT INTO source values(1, 'yes'); INSERT INTO source values(2, 'no');  INSERT INTO params VALUES(1,1,1); INSERT INTO params VALUES(2,1,2); INSERT INTO params VALUES(3,1,3);  INSERT INTO params VALUES(4,2,1); INSERT INTO params VALUES(5,2,3); INSERT INTO params VALUES(6,2,4); 

If i have a list of param values (say [1,2,3]), how do I find all the sources that have ALL of the values in the list (source 1, ‘yes’) in SQL?

Thanks

Answer 1

Edit Modified to handle case where there can be multiple occurances of the value for a given source.

Try this:

SELECT     * FROM     source WHERE     (         SELECT COUNT(DISTINCT value)         FROM params         WHERE params.source = source.id           AND params.value IN (1, 2, 3)     ) = 3 

You can rewrite it to a GROUP BY as well:

SELECT     source.* FROM     source     INNER JOIN params ON params.source = source.id WHERE     params.value IN (1, 2, 3) GROUP BY     source.id,     source.name HAVING     COUNT(DISTINCT params.value) = 3