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Asked: 2026-05-10T18:03:02+00:00

In the following snippet, using XmlReader, when I encounter an element. I would like

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In the following snippet, using XmlReader, when I encounter an element. I would like to read it as-is, including all attributes and namespace decoration in the element. Using the oXml.Name property, I am only able to get the tag name. Is there a function to get the tag itself?

oXml = XmlReader.Create(path, oXmlSettings) While oXml.Read()    Select Case oXml.NodeType       Case XmlNodeType.Element         'Read Element as-is          If taglist.contains(oXml.Name)            stringbuilder.Append(oXml.ReadOuterXml())          End If       Case XmlNodeType.Text          stringbuilder.Append(oXml.Value)    End Select End While

I have tried oXml.ReadOuterXml() but it returns the element and its subcontent. That could be acceptable, but how do I fast forward my XmlReader to ignore subsequent XmlNodeType.Text and XmlNodeType.EndElement that will happen when the element I just got from ReadOuterXml has been parsed?

UPDATED: For the following snippet, loc1 is in taglist, so is written using ReadOuterXml, but the parser fails to get the following ‘!’ character.

<para>   Test blabla <loc1 href='test'>complicated</loc1>! </para>
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  1. I haven’t tried it, but I wouldn’t expect that you’d have to fast forward the reader after calling ReadOuterXml. I’d expect the act of reading the outer XML to consume it.

    Have you tried it?

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