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Home/ Questions/Q 757549
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T15:22:34+00:00 2026-05-14T15:22:34+00:00

In the header, it is defined like: #if __LP64__ || (TARGET_OS_EMBEDDED && !TARGET_OS_IPHONE) ||

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In the header, it is defined like:

#if __LP64__ || (TARGET_OS_EMBEDDED && !TARGET_OS_IPHONE) || TARGET_OS_WIN32 || NS_BUILD_32_LIKE_64
typedef long NSInteger;
typedef unsigned long NSUInteger;
#else
typedef int NSInteger;
typedef unsigned int NSUInteger;
#endif

So does an UInt32 fit without problems into an NSUInteger (an unsigned int)? Where’s the difference between UInt32 and unsigned int?

And I assume that an unsigned long is bigger than an unsigned int?

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  1. Editorial Team
    Editorial Team
    2026-05-14T15:22:35+00:00Added an answer on May 14, 2026 at 3:22 pm

    I suppose the only difference between a UInt32 and an unsigned int is that a UInt32 is guaranteed to be 32 bits long, whereas an unsigned int technically could be shorter if you were running (say) on a < 32-bit operating system.

    However, given that the Mac and the iPhone are both at least 32-bit systems, it’s safe to use unsigned int, UInt32, and NSUInteger reasonably interchangeably. The only difference here is that a NSUInteger might be 64 bits long (on the Mac, when compiling for x86_64).

    As for your question of unsigned long versus unsigned int, UInt32 is typedef’d to an unsigned long, again indicating that it’s safe to use interchangeably. An unsigned long is guaranteed to be at least as big as an unsigned int.

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