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Home/ Questions/Q 9274647
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T16:24:09+00:00 2026-06-18T16:24:09+00:00

In the last line of the main function, why does &word2 differ from word2

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In the last line of the main function, why does &word2 differ from word2? Assume the right headers are in place. Thank you!

int main()
{
    char word1[20];
    char *word2;

    word2 = (char*)malloc(sizeof(char)*20);

    printf("Sizeof word 1: %d\n", sizeof (word1));
    printf("Sizeof word 2: %d\n", sizeof (word2));

    strcpy(word1, "string number 1");
    strcpy(word2, "string number 2");

    printf("%s\n", word1);
    printf("%s\n", word2);
    printf("Address %d, evaluated expression: %d\n", &word1, word1);
    printf("Address %d, evaluated expression: %d\n", &word2, word2); 
    //Why this one differ?
}
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  1. Editorial Team
    Editorial Team
    2026-06-18T16:24:10+00:00Added an answer on June 18, 2026 at 4:24 pm

    word2 is the address of the memory that you allocated using malloc.

    &word2 is the address of the variable named word2.

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