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Home/ Questions/Q 6375897
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T01:40:29+00:00 2026-05-25T01:40:29+00:00

In the latest Python (3.2): >>> l = [{}]*2 >>> l[1][‘key’] = ‘value’ >>>

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In the latest Python (3.2):

>>> l = [{}]*2
>>> l[1]['key'] = 'value'
>>> l
[{'key': 'value'}, {'key': 'value'}]

I expected l to be [{}, {'key': 'value'}] after this operation. Is it normal behaviour or a bug?

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  1. Editorial Team
    Editorial Team
    2026-05-25T01:40:30+00:00Added an answer on May 25, 2026 at 1:40 am

    Normal. Try using l = [{} for x in range(2)] instead.

    [{}]*2 does not actually make 2 different dictionaries – it makes a list with two references to the same dictionary. Thus, updating that dictionary makes changes show up for both items in the list, because both items are actually the same dictionary, just referenced twice.

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