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Home/ Questions/Q 6166677
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T22:22:43+00:00 2026-05-23T22:22:43+00:00

In the Learning OpenCV book: . . CvCapture *capture = cvCreateFileCapture(argv[1]); IplImage* frame; while(1)

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In the Learning OpenCV book:

.
.
CvCapture *capture = cvCreateFileCapture(argv[1]);
IplImage* frame;
while(1)
{
frame = cvQueryFrame(capture);
.
.
}

Here, we can see that *frame is a pointer. But, when we write the following frame = cvQueryFrame(capture);, we are not assigning an address to the pointer. What exactly will the values be that frame will hold in this case?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-23T22:22:44+00:00Added an answer on May 23, 2026 at 10:22 pm

    frame is pointer to an object of type IplImage. Presumably, the cvQueryFrame() function allocates an IplImage object and returns the address of this object. The statement

    frame = cvQueryFrame(capture);
    

    assigns the value of this returned pointer to frame. If indeed the function is allocating a new object you’ll probably be required to free this memory later by calling operator delete or some function like

    void cvDestroyFrame( IplImage * );
    

    Also the statement you make at the end of your question (“*frame is a pointer”) is not accurate – frame is a pointer; *frame means you’re de-referencing the pointer which makes its type IplImage.

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