Question

In the most general of cases, I have a query like below:

SELECT tutor_school.name, count(*), tutor_school.schoolid 

FROM tutor_school, tutor_attends, tutor_tutors_in 

WHERE 
tutor_school.schoolid = tutor_attends.schoolid and 
tutor_school.schoolid in ('1', '2', '3') and 
tutor_attends.userid=tutor_tutors_in.userid

group by tutor_school.schoolid LIMIT 0, 10

In essence, I want:

Name of School, Number of Students attending that school that tutor in any subject, Schoolid

What I’m actually getting is

Name of School, sum of all subjects taught by students at that school, schoolid — in other words, if student 1 tutors 3 subjects, student 2 tutors 5, then instead of returning 2 I get 8!

I’ve realized that the issue is with the following statement:

tutor_attends.userid=tutor_tutors_in.userid

This isn’t checking the existence of a given foreign key in a remote table, it’s giving a result for each instance of that key.

What I’m trying to figure out is how to bind it to limit it to simply the existence of the given key, not the number of times that key occurs. I know I’ve seen a case similar to this in my SQL class, but I can’t remember what the solution was.

Answer 1

Andrew is correct and here’s a concrete example of his solution (had to make assumptions on your table design):

SQL> SELECT * FROM tutor_school;

  SCHOOLID NAME
---------- --------------------
         1 School A
         2 School B
         3 School C


SQL> SELECT * FROM tutor_attends;

    USERID   SCHOOLID
---------- ----------
         1          1
         2          1
         3          2


SQL> SELECT * FROM tutor_tutors_in;

    USERID SUBJECT
---------- --------------------
         1 Math
         1 Science
         1 English
         2 English
         3 Math


SQL> SELECT tutor_school.name, COUNT(DISTINCT tutor_tutors_in.userid)
  2  FROM tutor_school, tutor_attends, tutor_tutors_in
  3  WHERE tutor_school.schoolid=tutor_attends.schoolid
  4  AND tutor_attends.userid=tutor_tutors_in.userid
  5  GROUP BY tutor_school.name
  6  /

NAME                 COUNT(DISTINCTTUTOR_TUTORS_IN.USERID)
-------------------- -------------------------------------
School A                                                 2
School B                                                 1