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Home/ Questions/Q 9229539
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T05:35:49+00:00 2026-06-18T05:35:49+00:00

In the simple program below command is pointing to 400 bytes on the heap.

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In the simple program below command is pointing to 400 bytes on the heap. Then I copy “./search ‘” to command, *buffer points to the next byte after ” ‘ ” (single quote). Starting the memory pointed by buffer I use memset to set 300 bytes to value 0x41 (ASCII ‘A’), then I append the closing single quote.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <strings.h>

int main(int argc, char *argv[]) {
    char *command = (char *)malloc(400);
    bzero(command, 400);

    strcpy(command, "./search \'");
    char *buffer = command + strlen(command);

    memset(buffer, 0x41, 300);
    strcat(command, "\'");

    system(command);
    free(command);
}

But when I look at *command and *buffer in gdb this is what I see.

char * command 0x601010 "./search '", 'A' <repeats 186 times>...
char * buffer  0x60101e 'A' <repeats 200 times>...

First I was expecting it to say repeats 299 times and second I was expecting both command and buffer repeats to be of similar value. Can someone please tell me what am I missing?

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  1. Editorial Team
    Editorial Team
    2026-06-18T05:35:50+00:00Added an answer on June 18, 2026 at 5:35 am

    From the GDB manual, section 10.8 Print Settings:

    set print elements number-of-elements

    Set a limit on how many elements of an array gdb will print. If gdb is printing a large array, it stops printing after it has printed the number of elements set by the set print elements command. This limit also applies to the display of strings. When gdb starts, this limit is set to 200. Setting number-of-elements to zero means that the printing is unlimited.

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