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Home/ Questions/Q 75969
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Asked: May 10, 20262026-05-10T20:35:58+00:00 2026-05-10T20:35:58+00:00

in the System.Linq namespace, we can now extend our IEnumerable’s to have the Any()

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in the System.Linq namespace, we can now extend our IEnumerable’s to have the Any() and Count() extension methods.

I was told recently that if i want to check that a collection contains 1 or more items inside it, I should use the .Any() extension method instead of the .Count() > 0 extension method because the .Count() extension method has to iterate through all the items.

Secondly, some collections have a property (not an extension method) that is Count or Length. Would it be better to use those, instead of .Any() or .Count()?

yea / nae?

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  1. 2026-05-10T20:35:58+00:00Added an answer on May 10, 2026 at 8:35 pm

    If you are starting with something that has a .Length or .Count (such as ICollection<T>, IList<T>, List<T>, etc) – then this will be the fastest option, since it doesn’t need to go through the GetEnumerator()/MoveNext()/Dispose() sequence required by Any() to check for a non-empty IEnumerable<T> sequence.

    For just IEnumerable<T>, then Any() will generally be quicker, as it only has to look at one iteration. However, note that the LINQ-to-Objects implementation of Count() does check for ICollection<T> (using .Count as an optimisation) – so if your underlying data-source is directly a list/collection, there won’t be a huge difference. Don’t ask me why it doesn’t use the non-generic ICollection…

    Of course, if you have used LINQ to filter it etc (Where etc), you will have an iterator-block based sequence, and so this ICollection<T> optimisation is useless.

    In general with IEnumerable<T> : stick with Any() ;-p

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