Question

In the Windsor IOC container is it possible to register a type that I’ve already got an instance for, instead of having the container create it?

Answer 1

There is a AddComponentInstance method on the Container’s Kernel property.

From the Unit Tests:

[Test] public void AddComponentInstance() {     CustomerImpl customer = new CustomerImpl();      kernel.AddComponentInstance('key', typeof(ICustomer), customer);     Assert.IsTrue(kernel.HasComponent('key'));      CustomerImpl customer2 = kernel['key'] as CustomerImpl;     Assert.AreSame(customer, customer2);      customer2 = kernel[typeof(ICustomer)] as CustomerImpl;     Assert.AreSame(customer, customer2); }  [Test] public void AddComponentInstance_ByService() {     CustomerImpl customer = new CustomerImpl();      kernel.AddComponentInstance <ICustomer>(customer);     Assert.AreSame(kernel[typeof(ICustomer)],customer); }  [Test] public void AddComponentInstance2() {     CustomerImpl customer = new CustomerImpl();      kernel.AddComponentInstance('key', customer);     Assert.IsTrue(kernel.HasComponent('key'));      CustomerImpl customer2 = kernel['key'] as CustomerImpl;     Assert.AreSame(customer, customer2);      customer2 = kernel[typeof(CustomerImpl)] as CustomerImpl;     Assert.AreSame(customer, customer2); }