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Home/ Questions/Q 630327
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T19:50:35+00:00 2026-05-13T19:50:35+00:00

In this answer to a question asking is doing Z this way portable the

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In this answer to a question asking “is doing Z this way portable” the idea is “boost does it this way, it means it is very portable”.

Can I just always consult boost sources to find the most portable way of doing something in C++? How can I judge for myself if boost is really such a collection of super-portable code?

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  1. Editorial Team
    Editorial Team
    2026-05-13T19:50:36+00:00Added an answer on May 13, 2026 at 7:50 pm

    There are some cases where Boost libraries exist precisely because they wrap very non-portable code. The most obvious examples are the file system and threading stuff.

    The telltale sign of this is a large use of Boost.Config macros. Boost code that doesn’t depend on Boost.Config (or other non-standard #ifdefs) will be highly portable.

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