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Home/ Questions/Q 7064193
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T04:48:14+00:00 2026-05-28T04:48:14+00:00

in this case, i’m using: – (IBAction)reset:(id) sender { if ((boxHide1.hidden = YES) &&

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in this case, i’m using:

- (IBAction)reset:(id) sender {

if ((boxHide1.hidden = YES) && (boxHide2.hidden = YES)) {
    resetHide.hidden = NO;
}

}

How can I do this? I have 12 items all together I need in the statement. Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-28T04:48:15+00:00Added an answer on May 28, 2026 at 4:48 am

    You could use the solution @Joe posted but as you can tell the code for hiding / unhiding could get very messy and hard to read.

    If you want to keep your code clean and easy to understand / maintain, I’d put all these buttons into a NSMutableArray and iterate through it to determine whether you want to show the reset button or not.

    BOOL showResetButton = YES;
    for (UIButton *button in buttonsArray)
    {
        if (button.hidden == NO) // If any of the buttons is not hidden do not show the reset button
            showResetButton = NO;
    }
    resetButton.hidden = showResetButton;
    
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