Question

In this code i want to iterate my array according to index value which is provided by code like one time i want to iterate and get output of ARGV[1] second time ARGV[3].

suppose

ARGV = ["-f","abc","-x","-p","wer"]

#!/usr/bin/env ruby

@lenght = ARGV.length
@factory_config_xml = ""
@num = 0

if @lenght != 0
    ARGV.each_with_index do |a , x|

        @num = @num + 1
        b = ARGV[@num]

        if ((a == "-f") && !(b.match "-") )

            @factory_config_xml = b
            x += 1
            @num = @num + 1

        elsif ((a == "-x") && !(b.match "-") )

            @factory_config_xml = b
            x += 1
            @num = @num + 1

        elsif ((a == "-p") && !(b.match "-") )

            @factory_config_xml = b
            x += 1
            @num = @num + 1
        end

    end
end


puts @factory_config_xml 

Answer 1

Instead of reinventing the wheel again, why don’t you use an option parser library to parse your program arguments.

For example with OptionParser your life would be much easier.

In this particular problem, incrementing the x variable by one won’t help you, because in the next iteration each_with_index will pass the next integer again. So, you should create your own loop:

i = 0
while (i < ARGV.length) do
  # do your stuff with the incrementing but take care to increment in each loop
end