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Home/ Questions/Q 8112599
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T02:33:24+00:00 2026-06-06T02:33:24+00:00

In this example we have 3 related tables on a SQLite database: CREATE TABLE

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In this example we have 3 related tables on a SQLite database:

CREATE TABLE test1 (
    c1 integer,
    primary key (c1)
);
CREATE TABLE test2 (
    c1 integer,
    c2 integer,
    primary key (c1, c2)
);    
CREATE TABLE test3 (
    c2 integer,
    c3 integer,
    primary key (c2)
);

Now I need to join all tables:

 test1 -> test2 (with c1 column)
          test2 -> test3 (with c2 column).

I have tried this solution but it doesn’t run:

SELECT 
   * 
   FROM test1 a 
        LEFT OUTER JOIN test2 b
                        LEFT OUTER JOIN test3 c
                          ON c.c2 = b.c2 
          ON b.c1=a.c1 

It gives me an error:
near "ON": syntax error.

Any help ?

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  1. Editorial Team
    Editorial Team
    2026-06-06T02:33:25+00:00Added an answer on June 6, 2026 at 2:33 am

    This is a simple misplacement of your ON statement. This conforms to SQL standard:

    SELECT * 
    FROM test1 a 
    LEFT OUTER JOIN test2 b ON b.c1=a.c1 
    LEFT OUTER JOIN test3 c ON c.c2=b.c2 
    

    This is explained in further depth here.

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