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Home/ Questions/Q 8467649
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T15:42:22+00:00 2026-06-10T15:42:22+00:00

In this implementation does hand will be evaluated each time and return another list

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In this implementation does hand will be evaluated each time and return another list ?

foreach (Card card in hand.Cards)
{ 

}

Should we replace the above implementation with the following?

var cards = hand.Cards;
foreach (Card card in cards)
{ 

} 
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T15:42:23+00:00Added an answer on June 10, 2026 at 3:42 pm

    No. Actually the two snippets result in the same code.
    In the snippet below:

    foreach (Card card in hand.Cards)
    { 
    
    }
    

    hand.Cards is going to be called only once.

    Edit:

    I’ve created a small snippet, that I hope will show that there is no difference at all:

    void Main()
    {
        Hand hand = new Hand();
        foreach( var card in hand.Cards() )
        {
            Console.WriteLine("{0}", card);
        }
    
        var allCards = hand.Cards();
        foreach( var anotherCard in allCards )
        {
            Console.WriteLine("{0}", anotherCard);
        }
    }
    
    public class Card
    {
    private string _cardName;
    public Card( string cardName )
        {
            this._cardName = cardName;
        }
    
        public override string ToString()
        {
            return this._cardName;
        }
    }
    
    public class Hand
    {
        public IEnumerable<Card> Cards()
        {
            yield return new Card("Ace");
            yield return new Card("King");
        }
    }
    

    The otuput (for both methods) is as follows:

    Ace
    King
    Ace
    King
    
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