Question

In this loop:

while(a < 100){
    a=a+1;
    for(i = 0;i < arr.length;i++){
        if(x < arr[i]){
            arr2[i] = arr2[i] - z;
            x = x - z;
            if(x > arr[i]) break;
        }
    }
}

The ith element may be greater than x causing the break but i+1 may
be less than x and I want to subtract x from i+1, how can I make the loop just skip arr[i] and move on to arr[i+1] without breaking the loop altogether and without starting an iteration from the top?

An example of my output is arr2=(0,0,0,2,0,0,5) where x=3 so my loop terminates at 2 because its less than 3 but I still want to subtract from 5.

Answer 1

I think you maybe intend this, but I cannot imagine what you try to achieve.
Try the algorithm on paper.

for (int i = 0; i < arr.length; i++){
    if (x < arr[i]) {
        arr2[i] -= z;
        x -= z;
        if (x <= 0) {
            break;
        }
        // Continue with smaller x (assuming z > 0) for rest of arr.
    }
}

---

On the for loop:

for (START; CONDITION; STEP) {
    STMT1;
    continue;
    STMT2;
 }

is equivalent to:

 START;
 loop:
     if (!CONDITION) {
         goto endloop;
     }
     STMT1;
     goto step;
     STMT2;
 step:
     STEP;
     goto loop;
 endloop: