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Asked: 2026-05-11T12:01:49+00:00

In this ParserFactory.java String className = System.getProperty(org.w3c.css.sac.parser); if (className == null) { throw new

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In this ParserFactory.java

String className = System.getProperty('org.w3c.css.sac.parser'); if (className == null) {     throw new NullPointerException('No value for sac.parser property');  //line 35 } else {     return (Parser)(Class.forName(className).newInstance()); }

When I run this DemoSAC.java file as Java Application in Eclipse, I got

Exception in thread 'main' java.lang.NullPointerException: No value for sac.parser property at org.w3c.css.sac.helpers.ParserFactory.makeParser(ParserFactory.java:35)

What exactly is the ‘org.w3c.css.sac.parser’ property? How do I set it under Windows? What should I set it to?

Thanks!

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1 Answer

  1. If you don’t want to modify code, you can also set a Java property in Eclipse’s Java launch configuration dialog. You specify a ‘VM option’ in the ‘Arguments’ tab . To set the property to ‘org.w3c.flute.parser.Parser’ as suggested by javamonkey79, you would specify:

    -Dorg.w3c.css.sac.parser=org.w3c.flute.parser.Parser

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