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Home/ Questions/Q 7660251
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T13:26:26+00:00 2026-05-31T13:26:26+00:00

In this piece of code taken from http://drdobbs.com/cpp/184403774 : template <class L, class R>

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In this piece of code taken from http://drdobbs.com/cpp/184403774:

template <class L, class R>
class MinResult {
    L& lhs_;
    R& rhs_;
public:
    operator L&() { return lhs_ < rhs_ ? lhs_ : rhs_; }   // <----
    operator R&() { return lhs_ < rhs_ ? lhs_ : rhs_; }   // <----
    MinResult(L& lhs, R& rhs) : lhs_(lhs), rhs_(rhs) {}
};

What is the code above trying to do at lines pointed by arrows?

I am a beginner in C++ and I understand that we can override / define operator() by defining it.

But then shouldn’t it be defined like this

L& operator() { return lhs_ < rhs_ ? lhs_ : rhs_; }

I am sure this is some differenct syntax since operator() is supposed to be one word. Also, you cannot define two of them with different return types.

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  1. Editorial Team
    Editorial Team
    2026-05-31T13:26:26+00:00Added an answer on May 31, 2026 at 1:26 pm

    No this is type cast operator.

    You can define

    operator type() const
    

    As operator that allows to cast to the type. For example

    class date {
    public:
       operator time_t() const; // convert to time_t
    };
    

    The operator() has a different purpose, it allows to use the class as “function” and this is not the case here

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