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Home/ Questions/Q 5980095
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T21:45:10+00:00 2026-05-22T21:45:10+00:00

In this program: int x, y; int *old = &x; int *new = &y;

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In this program:

int x, y; 
int *old = &x;
int *new = &y;
int * volatile cur = &x;

OSAtomicCompareAndSwapPtrBarrier(old, new, &cur);

I get this warning:

Incompatible pointer passing ‘int *volatile *’ to parameter of type ‘void *volatile *’

on XCode 4.0.1’s default compiler. (Live Issues, actually.)

Now, I know that in general I can’t cast int** to void** . But if I don’t, I don’t see any way to compare-and-swap and int* without getting the above warning. Should I just ignore the warning, assuming it’s a relic from a time of non-uniform pointer sizes, or am I misunderstanding something?

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  1. Editorial Team
    Editorial Team
    2026-05-22T21:45:10+00:00Added an answer on May 22, 2026 at 9:45 pm

    I think the warning says that the compiler considers implicit conversion from pointer-to-pointer-to-int to pointer-to-pointer-to-void as dangerous. It’s not as if you could not do such a conversion; the standard says a pointer can be converted to a pointer to an object of different type, as long as type alignment requirements are satisfied. But sometimes, e.g. in case of strict aliasing being used, it can potentially lead to problems.

    I believe in your case the warning can be ignored, or possibly eliminated with explicit casts:

    bool result = OSAtomicCompareAndSwapPtrBarrier(old, new, &(void*)cur);
    

    Also, make sure you do not forget to check the return value; ignoring the fact that atomic compare-and-swap may not succeed (due to concurrent modifications) is rarely safe.

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