In this question, I have an endless sequence using Python generators. But the same code doesn’t work in Python 3 because it seems there is no next() function. What is the equivalent for the next function?
def updown(n):
while True:
for i in range(n):
yield i
for i in range(n - 2, 0, -1):
yield i
uptofive = updown(6)
for i in range(20):
print(uptofive.next())
In Python 3, use
next(uptofive)instead ofuptofive.next().The built-in
next()function also works in Python 2.6 or greater.