Question

In this simple sparql query I get a list of subjects whose object is 42

SELECT ?v WHERE { ?v ?p 42 }

If I add ?p as a variable

SELECT ?v ?p WHERE { ?v ?p 42 }

I will get two entities per row, the subject and the predicate.
What if I wanted three entities, so including the 42? Something like:

SELECT ?v ?p ?m WHERE { ?v ?p (42 as m) }

Answer 1

Standard SPARQL 1.0 does not really allow that. There may be some implementation-specific extensions for doing it, though.

As a workaround, if the data contains a triple with 42 as an object literal, you can do it e.g. like this:

SELECT ?v ?p ?m { ?v ?p 42, ?m FILTER(?m=42)}

which is equivalent with

 SELECT ?v ?p ?m WHERE { ?v ?p 42 . ?v ?p ?m FILTER(?m=42)}

as you can write graph patterns sharing the same subject and predicate with the comma object list notation, and the WHERE keyword is optional.

For efficiency, you want to use basic graph patterns to reduce the working triple to a smaller set and only then apply FILTER expressions to further prune the results.