Question

In thsi example:

int a[2][2]={{1,2},{3,4}};
int *p=a[0];
cout<<p;
cout<<&a[0][0];

Both gives the same output.
Then why am I not able to call function (say fun)like this and loop through the array:

fun(a[0]);

fun(int *p)
{
cout<<p[1][1];
}

Answer 1

fun(a[0]); //this looks OK

void fun(int *p) // this is OK if you add return type'
^^^^
{
   cout<<p[1][1]; //NOT OK!  You can't have 2 indices on an `int*`
   cout << p[1]; // OK, will print a[0][1]
}