Question

In XAML, how do you define a context menu for treeviewitems that are distinguished by different attributes?

Answer 1

XAML

<TreeView Name="SolutionTree"  BorderThickness="0" SelectedItemChanged="SolutionTree_SelectedItemChanged"  >
  <TreeView.Resources>
    <ContextMenu x:Key ="SolutionContext"  StaysOpen="true">
      <MenuItem Header="Add..." Click="AddFilesToFolder_Click"/>
      <MenuItem Header="Rename"/>
    </ContextMenu>
    <ContextMenu x:Key="FolderContext"  StaysOpen="true">
      <MenuItem Header="Add..." Click="AddFilesToFolder_Click"/>
      <MenuItem Header="Rename"/>
      <MenuItem Header="Remove"/>
      <Separator/>
      <MenuItem Header="Copy"/>
      <MenuItem Header="Cut"/>
      <MenuItem Header="Paste"/>
      <MenuItem Header="Move"/>
    </ContextMenu>
  </TreeView.Resources>
</TreeView>

C-sharp

private void SolutionTree_SelectedItemChanged(object sender, RoutedPropertyChangedEventArgs<object> e)
{
    TreeViewItem SelectedItem = SolutionTree.SelectedItem as TreeViewItem;
    switch (SelectedItem.Tag.ToString())
    {
        case "Solution":
            SolutionTree.ContextMenu = SolutionTree.Resources["SolutionContext"] as System.Windows.Controls.ContextMenu;
            break;
        case "Folder":
            SolutionTree.ContextMenu = SolutionTree.Resources["FolderContext"] as System.Windows.Controls.ContextMenu;
            break;
    }
}