Question

In XSL is function like CONTAIN, that if i have number with simbol like “123112’+:” then doesn’t take it.

to be more precise:

<Number>111111</Number>
<Number>123123+</Number>
<Number>222222</Number>
<Number>222222+</Number>

answer:

111111
222222

I’m stuck with xslt 1.0 version

Answer 1

Another approach, exploiting number to boolean conversion.

<xsl:stylesheet
    version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="text"/>

    <xsl:template match="/*">
        <xsl:apply-templates select="Number[boolean(number()) or . = 0]"/>
    </xsl:template>

    <xsl:template match="Number">
        <xsl:value-of select="."/>
        <xsl:text>&#xA;</xsl:text>
    </xsl:template>

</xsl:stylesheet>

With input:

<Numbers>
    <Number>111111</Number>
    <Number>123123+</Number>
    <Number>222222</Number>
    <Number>222222+</Number>
</Numbers>

Correct result:

111111
222222

Quoting the spec:

The boolean function converts its
argument to a boolean as follows: a
number is true if and only if it is
neither positive or negative zero nor
NaN