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Home/ Questions/Q 216739
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T18:35:33+00:00 2026-05-11T18:35:33+00:00

#include <boost/ptr_container/ptr_vector.hpp> #include <iostream> using namespace std; using namespace boost; struct A { ~A()

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#include <boost/ptr_container/ptr_vector.hpp>
#include <iostream>

using namespace std;
using namespace boost;

struct A {
    ~A() { cout << "deleted " << (void*)this << endl; }
};

int main() {
    ptr_vector<A>   v;
    v.push_back(new A);
    A   *temp = &v.front();
    v.release(v.begin());
    delete temp;
    return 0;
}

outputs:

deleted 0x300300
deleted 0x300300
c(6832) malloc: *** error for object 0x300300: double free
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  1. Editorial Team
    Editorial Team
    2026-05-11T18:35:33+00:00Added an answer on May 11, 2026 at 6:35 pm

    ptr_vector<A>::release returns a ptr_vector<A>::auto_type, which is a kind of light-weight smart pointer in that when an auto_type item goes out of scope, the thing it points to is automatically deleted. To recover a raw pointer to the thing, and keep it from being deleted by the auto_ptr that’s holding it, you need to call release on that too:

    int main() {
        ptr_vector<A> v;
        v.push_back(new A);
        A *temp=v.release(v.begin()).release();
        delete temp;
        return 0;
    }
    

    The first release tells the ptr_vector to give it up; the second tells the auto_ptr to give it up too.

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