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Home/ Questions/Q 3600764
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Editorial Team
  • 0
Editorial Team
Asked: May 18, 20262026-05-18T20:32:11+00:00 2026-05-18T20:32:11+00:00

#include <boost/regex.hpp> #include <string> #include <iostream> using namespace boost; static const regex regexp( std::vector<

  • 0
#include <boost/regex.hpp>
#include <string>
#include <iostream>

using namespace boost;
static const regex regexp(
        "std::vector<"
            "(std::map<"
                   "(std::pair<((\\w+)(::)?)+, (\\w+)>,?)+"
             ">,?)+"
        ">");

std::string errorMsg =
"std::vector<"
        "std::map<"
                "std::pair<Test::Test, int>,"
                "std::pair<Test::Test, int>,"
                "std::pair<Test::Test, int>"
        ">,"
        "std::map<"
                "std::pair<Test::Test, int>,"
                "std::pair<Test::Test, int>,"
                "std::pair<Test::Test, int>"
        ">"
">";
int main()
{
    smatch result;
    if(regex_match(errorMsg, result, regexp))
    {  
        for (unsigned i = 0; i < result.size(); ++i)
        {  
            std::cout << result[i] << std::endl;
        }
    }

//    std::cout << errorMsg << std::endl;

    return 0;
}

this produces:

terminate called after throwing an instance of 'boost::exception_detail::clone_impl<boost::exception_detail::error_info_injector<std::runtime_error>
>'   what():  Ran out of stack space trying to match the regular expression.

compiled with

g++ regex.cc -lboost_regex

EDIT

my platform:

g++ (Ubuntu/Linaro 4.4.4-14ubuntu5) 4.4.5
libboost-regex1.42
Intel(R) Core(TM)2 Quad CPU Q9400 @ 2.66GHz
So the latest Ubuntu 64 bit
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T20:32:12+00:00Added an answer on May 18, 2026 at 8:32 pm

    ((\\w+)(::)?)+ is one of the so called “pathological” regular expressions — it’s going to take exponential time, because you have two expressions which are dependent upon each other one right after the other. That is, it fails due to catastrophic backtracking.

    Consider if we follow the example of the link, and reduce “something more complicated” to “x”. Let’s do that with \\w:

    • ((x+)(::)?)+

    Let’s also assume that our input is never going to have ::. Having this actually makes the regex more complex, so if we throw out complexity then we really should be making things simpler if nothing else:

    • (x+)+

    Now you’ve got a textbook nested quantifier problem like that detailed in the link above.

    There are a few ways to fix this but the simplest way is probably to just disallow backtracking on the inner match using the atomic group modifier “(?>“:

    • ((?>\\w+)(::)?)+
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