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Editorial Team
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Asked: 2026-05-11T22:27:04+00:00

#include <cstring> int main() { char *pName = new char[10]; char dummy[] = dummy;

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#include <cstring>
int main()
    {
    char *pName = new char[10];
    char dummy[] = "dummy";
    strcpy(pName + 0,dummy);//how this is different from -->this works
    strcpy(pName[0],dummy);//this one...--> error C2664: 'strcpy' : 
                           //cannot convert parameter 1 
                           //from 'char' to 'char *'

    }
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1 Answer

  1. Editorial Team
    • pName[0] is the first element in a character array (one character)
    • pName is a shortcut to &pName[0] (a pointer to the first element of your array)

    The reason you are getting your error is because strcpy expects a pointer to a char (char*), and not a char value (which is what pName[0] is)

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