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Home/ Questions/Q 4018726
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Editorial Team
  • 0
Editorial Team
Asked: May 20, 20262026-05-20T10:01:07+00:00 2026-05-20T10:01:07+00:00

#include <iostream> class MyClass { public: MyClass() : mFirst() { } int mFirst; int

  • 0
#include <iostream>

class MyClass
{
public:
    MyClass() :
        mFirst()
    {
    }

    int mFirst;
    int mSecond;
};


int main()
{
    MyClass mc;
    std::cout << "mc.mFirst: " << mc.mFirst << std::endl;
    std::cout << "mc.mSecond: " << mc.mSecond << std::endl;

    int a;
    std::cout << "a: " << a << std::endl;
    return 0;
}

What is the expected output of this program?

I would think only MyClass.mFirst will be initialized to zero. However GCC initializes them all to zero, even with optimizations enabled:

$ g++ -o test -O3 main.cpp
$ ./test
mc.mFirst: 0
mc.mSecond: 0
a: 0

I’d like to know:

  1. How is each value initialized according to the C++ standard?
  2. Why does GCC initialize them all to zero?

Update

According to Erik the values are zero because my stack happens to contain zeroes. I tried forcing the stack to be non-zero using this construct:

int main()
{
    // Fill the stack with non-zeroes
    {
        int a[100];
        memset(a, !0, sizeof(a));
    }
    MyClass mc;
    std::cout << "mc.mFirst: " << mc.mFirst << std::endl;
    std::cout << "mc.mSecond: " << mc.mSecond << std::endl;

    int a;
    std::cout << "a: " << a << std::endl;
    return 0;
}

However, the output stays the same:

mc.mFirst: 0
mc.mSecond: 0
a: 0

Can anyone explain why?

Update 2

Ok I figured it out. GCC was probably optimizing away unused variables.

This application shows the expected behavior:

#include <iostream>

struct MyClass
{
    MyClass() : mFirst() { }

    MyClass(int inFirst, int inSecond) : mFirst(inFirst), mSecond(inSecond) { }

    int mFirst;
    int mSecond;
};


int main()
{
    // Fill the stack with non-zeroes
    // Use volatile to prevent GCC optimizations.
    {
        volatile MyClass mc(1, 2);
        volatile int a = 3;
    }

    {
        volatile MyClass mc;
        volatile int a;

        std::cout << "mc.mFirst: " << mc.mFirst << std::endl;
        std::cout << "mc.mSecond: " << mc.mSecond << std::endl;
        std::cout << "a: " << a << std::endl;
    }
    return 0;
}

Output:

$ g++ -o test main.cpp
$ ./test 
mc.mFirst: 0
mc.mSecond: 2
a: 3
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T10:01:07+00:00Added an answer on May 20, 2026 at 10:01 am

    They’re (EDIT: With “They” i refer to mSecond and a which are not explicitly initialized) not initialized. Your stack happens to contain 0’s so that’s the values you get.

    8.5/9:

    If no initializer is specified for an
    object, and the object is of (possibly
    cv-qualified) non-POD class type (or
    array thereof), the object shall be
    default-initialized; if the object is
    of const-qualified type, the
    underlying class type shall have a
    user-declared default constructor.
    Otherwise, if no initializer is
    specified for a nonstatic object, the
    object and its subobjects, if any,
    have an indeterminate initial
    value; if the object or any of its
    subobjects are of const-qualified
    type, the program is ill-formed.

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