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Home/ Questions/Q 4054746
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T14:36:52+00:00 2026-05-20T14:36:52+00:00

#include <iostream> #define n 255 using namespace std; int main() { int i=n; int

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#include <iostream>
#define n 255

using namespace std;


int main()
{
int i=n;
int *ptr=&i;
int const *ptr_1=&i;
const int *ptr_2=&i;
const int * const ptr_3=&i;
}

Why does this Code Compile in Visual C++, Dev C++ and G++?
Link to – Ideone –

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  1. Editorial Team
    Editorial Team
    2026-05-20T14:36:53+00:00Added an answer on May 20, 2026 at 2:36 pm

    It does compile, because all those pointers ether don’t change const-qualification of the variable access or enforce the qualification, but none of them tries to loosen the qualification.

    For example:

    const int var;
    int* address = &var; //illegal - tries to remove const
    

    would try to get non-const access to a const variable and that’s illegal, but

    int var;
    const int* address = &var; //legal - only adds const
    

    tries to get const access to a non-const variable and that’s legal since a non-const variable does allow const-only access.

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