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Home/ Questions/Q 6058889
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T08:38:59+00:00 2026-05-23T08:38:59+00:00

#include <iostream> #include <exception> using std::cout; using std::endl; class test { public: test() {

  • 0
#include <iostream>
#include <exception>
using std::cout;
using std::endl;
class test
{
 public:
    test()
    {
        cout<<"constructor called"<<endl;
    }
    ~test()
    {
        cout<<"destructor called"<<endl;
    }
    void fun(int x)
    {
       throw x;
    }
};

int main()
{
    try
    {
        static test k;          
        k.fun(3);
    }
    catch(int k)
    {
        cout<<"exception handler"<<endl;
    }
}

When the exception is thrown, then during the stack unwinding process, I think only local objects are destroyed, not static or heap objects. If this is true, I am not sure why the class (test) destructor is called? Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T08:39:00+00:00Added an answer on May 23, 2026 at 8:39 am

    The test destructor is called after main exits.

        catch(int k)
        {
            cout<<"exception handler"<<endl;
        }
        // Added this line
        std::cout << "Main Exiting\n";
    }
    

    Now testing

    > g++ test.cpp
    > ./a.out
    constructor called
    exception handler
    Main Exiting
    destructor called
    

    Static (static storage duration objects) are destroyed in the reverse order of creation after main exits.

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