Question

#include <iostream>

int main()
{
    int myArray[5];     // array of 5 integers lol
    int i;
    for (i=0; i<5; i++ )  // 0 - 4
    {
        std::cout << "Value for myArray[" << i << " ]: ";
        std::cin >> myArray[i];
    }
    for (i = 0; i<5; i++)
    std::cout << i << ": " << myArray[i] << std::endl;
    return 0;
}

Why is i++ required for this program to work?

Answer 1

Because if you don’t execute i++ (or any other statement which increments i), i will remain 0, the condition i < 5 will always remain true and the loop will never end.