Question

#include <iostream>

using namespace std;

class Sample{
public:
   enum{ x = 10 };
};

int main(){
   cout<<Sample::x<<endl;
   return 0;
}

Why x which is enum in class is accessible using scope resolution operator in main function?

Answer 1

I assume you are asking why you do not have to instantiate a Sample to access x. The reason is that enums are like typedefs: they create a new type, they don’t create a variable. You can access Sample::x the same way you could access a typedef or a struct/class declaration inside the class.