Question

#include <iostream>

using namespace std;

class test{
public:
    test() { cout<<"CTOR"<<endl; }
    ~test() { cout<<"DTOR"<<endl; }
};

int main()
{
 test testObj();
 cout<<"HERE"<<endl;

} 

Output:

HERE

Compiler skips the line “test testObj(); ” and compiles the rest with warning and when run will generate the output. The warning is “prototyped function not called (was a variable definition intended?) in VC++ 2008. Why does it not throw an error?

Answer 1

Because it’s not an error.

Your code has fallen foul of the most-vexing parse (in summary, test testObj(); doesn’t define a variable, it declares a function).