Question

#include <iostream>
using namespace std;

void fn(const void *l) {
    // How to print the value of l. The below line is giving error
    cout << "***" << *l;
}

int main() {
    cout << "Hello World!";
    int d = 5;

    fn((char *) &d);
    return 0;
}

Error:

In function ‘void fn(const void*)’:
Line 8: error: ‘const void*’ is not a pointer-to-object type
compilation terminated due to -Wfatal-errors.

Tried Casting as seen below. It didnt not help. Please provide suggestions.

#include <iostream>
using namespace std;

void fn(const void *l) {
    // How to print the value of l. The below line is giving error
    int *pInt = static_cast<char*>(l);
    cout << *pInt;
}

int main() {
    cout << "Hello World!";
    int d = 5;

    fn((char *) &d);
    return 0;
}

In function ‘void fn(const void*)’:
Line 9: error: static_cast from type ‘const void*’ to type ‘char*’ casts away constness
compilation terminated due to -Wfatal-errors

Answer 1

cout << "***" << *(int*)l ;