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Home/ Questions/Q 7803565
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T01:37:27+00:00 2026-06-02T01:37:27+00:00

#include stdafx.h #include <iostream> using namespace std; class thing{ public: int stuff, stuff1, stuff2;

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#include "stdafx.h"
#include <iostream>
using namespace std;

class thing{
public:
    int stuff, stuff1, stuff2;

    void thingy(int stuff, int *stuff1){
        stuff2=stuff-*stuff1;
    }
}

int main(){
    thing t;
    int *ptr=t.stuff1;
    t.thingy(t.stuff, *ptr);
}

I’ve been practicing classes, and pointers in C++. What i’m trying to do is have the function thingy modify the stuff2 data member in the thing class by passing a pointer to the value of stuff1. How do I go about doing this?

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  1. Editorial Team
    Editorial Team
    2026-06-02T01:37:29+00:00Added an answer on June 2, 2026 at 1:37 am

    You are creating a variable of type pointer-to-int: if you want a pointer to t.stuff1, take its address:

    int* ptr = &t.stuff1;
            ___^ here you are taking a reference (address)
    

    Then, pass that pointer to your thing::thingy method:

    t.thingy(t.stuff, ptr);
                    __^ don't dereference the pointer, your function takes a pointer
    
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