Question

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char print_two(char *reg, char *s)
{
    int i, l_s = (int) strlen(s), l_reg = (int) strlen(reg);
    for(i = 0; i < l_reg; i++)
    {
        printf("\n %c \n", reg[i]);
    }
    return 0;
}

int main(void)
{
    char reg;
    printf("Give a rule: ");
    scanf("%s", &reg);

    char s;
    printf("Give a string: ");
    scanf("%s", &s);

    print_two(&reg, &s);
    return 0;
} 

Program start:

Give a rule: qwert
Give a string: asdf
result:
d
q
a
s
d
f

How I can avoid overwrite reg by s?

I tried with realloc, malloc – 0 effect.

Two variables should be dynamic.

Is it possible to do?

---

user give 55 chars -> array 55

user give 100 chars -> array 100

Answer 1

Based on your comments to other answers, if you are ok with using GNU library extensions (mostly on Linux, or on Windows MinGW), you can use %ms in scanf format string, like this:

char *reg = NULL; // set to NULL to get segfault on uninitialized use
printf("Give a rule: ");
scanf("%ms", &reg); // scanf will malloc enough space to reg

// check for null in case scanf failed to read anything for some reason
// could also check return value of scanf, which is number of items it got
if (reg != NULL) {
  // process reg
}

free(reg); // free(NULL) is not an error, it just does nothing
reg = NULL; // set to NULL to get segfault on uninitialized use

Other answers show how to use a buffer with fixed size, which is standard C. Though according to man scanf notes section, %ms might be in a future POSIX standard. GNU also has older %as, but %ms should be preferred when it’s supported (ie. in any modern GNU system).