Question

#include <stdio.h>
#include <string.h>

int main(void) {
    char *w;
    strcpy(w, "Hello Word");
    printf("%s\n", w);
    return 0;
}

What is wrong with the way the char pointer is used in the above code?

Answer 1

Ok, you did not ask to the system for memory, to use it with the string. This code will work

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main() {
   char w[11];
   strcpy(w, "Hello Word");
   printf("%s\n", w);
   return 0;
}

That code declare w as an array of char, reserving the memory space for it. Other alternative is to use malloc or calloc for the char pointer. Read about that.