Question

  #include <stdio.h>
  #include<string.h>
  #include<stdlib.h>

  int main()
  {
     char *words[] = {"mHello", "kWorld", "kHow", "9Are", "3You?"};
     char **parsed = malloc(5);
     int i;
     for (i = 0; i < 5; i++)
     {
        int n = strlen(words[i]);
        parsed[i] = malloc(n);
        strncpy(parsed[i], words[i] + 1, n);
        printf("[%s] ", parsed[i]); 
     }
     printf("\n----------------------\n");
     for (i = 0; i < 5; i++)
       printf("[%s] ", parsed[i]);
         return 0;
  }

parsed[i] contains words[i] without the first character.

The output is

 [Hello] [World] [How] [Are] [You?]
 ----------------------
 [▒▒ o] [World] [How] [Are] [You?]

Why does the first printf call to parsed[0] work correctly while the second one doesn’t ?

Also, if I remove one element from words, this code works correct. What is going on ?

Answer 1

Your malloc is not allocating the correct space for pointers to strings though, it should be

parsed = malloc(sizeof(char*)*5)