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Home/ Questions/Q 6962159
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T15:37:25+00:00 2026-05-27T15:37:25+00:00

#include <stdio.h> int main (int argc, const char * argv[]) { static struct item

  • 0
#include <stdio.h>

int main (int argc, const char * argv[])
{
static struct item
{
    char code;
    float price;
}
table[] = 
{
    {'a', 3.29},
    {'b', 2.99},
    {'c', 0.59},
    {'d', 1.59},
    {'e', 2.39}
};

char item_code[2];
int quantity;
int i;

do {
    printf("Enter item code: ");
    scanf("%1s", item_code);

    if (*item_code != '.') {
        for (i=0; i< sizeof(table)/sizeof(struct item)
             && table[i].code != *item_code; i++);

        if (i < sizeof(table)/sizeof(struct item)) {
            printf("Enter quantity: ");
            scanf("%d", &quantity);
            printf("\nUnit price = %.2f, total price = %.2f.\n\n\n",
                   table[i].price, quantity * table[i].price);
        }
        else
            printf("\nItem code %c does not exist. \n\n\n", *item_code);
    }
} while (*item_code != '.');
printf("Thank you.\n");
return 0;
}

I am a newbie. I am unable to understand the second “for loop” in the above program. Why is sizeof being used? What exactly is the value of “i” each time the loop is executed?
Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-27T15:37:25+00:00Added an answer on May 27, 2026 at 3:37 pm

    Let’s examine some simple code in a system where integers are four bytes long:

    int xyzzy[] = {3,1,4,1,5,9,2,6,5,3,5,8,9};       // 13 integers
    printf ("%d\n"", sizeof(xyzzy));                 // 13 * 4 = 52
    printf ("%d\n"", sizeof(int));                   //           4
    printf ("%d\n"", sizeof(xyzzy) / sizeof(int));   // 52 / 4 = 13
    

    As per that final line, that calculation is a way to get the number of items in an array.

    As an aside, I prefer the construct:

    sizeof(xyzzy) / sizeof(*xyzzy)
    

    since that will continue to work even if I change the type of xyzzy to double for example. It means I only need to change the one line where the variable is declared rather than hunting for all the size calculations as well.

    In fact I even have a favorite macro for this:

    #define numof(x) (sizeof(x) / sizeof(*x))
    

    to make my code a little smaller.

    In terms of what that for loop is doing exactly (and, by the way, it’s not technically the second for loop since there’s only one, but it is the second loop), it basically iterates through every value of i (staring at 0, the first index) until it reaches either the point beyond the last element or it finds an element with the desired item code.

    On exit from that loop, i will be set to the number of elements if the item code wasn’t found or set to the correct index if it was found, hence the if statement following that for loop.

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