Question

#include <stdio.h> int main() {     unsigned long long int num = 285212672; //FYI: fits in 29 bits     int normalInt = 5;     printf('My number is %d bytes wide and its value is %ul. A normal number is %d.\n', sizeof(num), num, normalInt);     return 0; } 

Output:

My number is 8 bytes wide and its value is 285212672l. A normal number is 0. 

I assume this unexpected result is from printing the unsigned long long int. How do you printf() an unsigned long long int?

Answer 1

Use the ll (el-el) long-long modifier with the u (unsigned) conversion. (Works in windows, GNU).

printf('%llu', 285212672);