Question

#include <stdio.h>
main()
{
    int a[] ={ 1,2,3,4,5,6,7};
    char c[] = {' a','x','h','o','k'};
    printf("%d ", (&a[3]-&a[0]));
}

The output of the program is 3. However , the difference in the outputs of values obtained below is 12.Can someone please explain the ambiguity.

#include <stdio.h>
main()
{
    int a[] ={ 1,2,3,4,5,6,7};
    char c[] = {' a','x','h','o','k'};
    printf("%d     %d ", &a[3],&a[0]);
}

Answer 1

This is called pointer arithmetics. The result is the values divided by sizeof(int)

If the difference in bytes is 12, and the size of int is 4, than the result is 12/4=3

BTW, when printing addresses use the format specifier %p:

printf("%p     %p ", &a[3],&a[0]);