Question

#include <stdio.h>
main()
{
    typedef struct{
        char *name;
        int age;
    }person[5];

    int i;
    for (i=0;i<5;i++){
        printf ("name:");
        scanf("%s",person[i].name);
        printf("\nage:");
        scanf("%d",&person[i].age);}

    for (i=0;i<5;i++){
        printf ("person:%d",i);
        printf ("name:%s",person[i].name);
        printf ("age:%d",person[i].age);
    }
}

this is the sample program i have. But while compiling i keep getting the error “expected expression before person in line 10,12,16 and 17? What am i doing wrong?

Answer 1

To fix the syntax error, remove the typedef keyword (you’re trying to declare a variable, not a type).

Better yet, change to:

typedef struct{
    char *name;
    int age;} Person;

Person person[5];

Also, the following is wrong:

scanf("%s",person[i].name);

You need to first allocate memory for person[i].name (for example, using malloc()).

Lastly, the %s format specifier in the following line is not correct:

printf ("age:%s",person[i].age);