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Home/ Questions/Q 705557
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T04:04:03+00:00 2026-05-14T04:04:03+00:00

#include <string.h> #include <stdlib.h> #include <stdio.h> int main(void) { unsigned char *stole; unsigned char

  • 0
#include <string.h>
#include <stdlib.h>
#include <stdio.h>
int main(void)
{
        unsigned char *stole;
        unsigned char pass[] = "m4ak47";
        printf("Vnesi password: \t");
        scanf("%s", stole);
        if(strncmp(stole, pass, sizeof(pass)) != 0)
        {
                printf("wrong password!\n");
                exit(0);
        }
        else
                printf("Password correct\n");
        printf("some stuf here...\n\n");
        return 0;
}

This program is working nice, but with one problem – if the password is correct then it DOES do the printing of ‘some stuf here…’ but it also shows me segmentation fault error at the end. Why ?

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  1. Editorial Team
    Editorial Team
    2026-05-14T04:04:03+00:00Added an answer on May 14, 2026 at 4:04 am

    unsigned char *stole;
    The above statement declares stole as a pointer to unsigned char and contains garbage value, pointing to some random memory location.

    scanf("%s", stole);
    The above statement tries to store some string to memory pointed by stole which is being used by another program (atleast not allocated to your program for use). So, when scanf attempts to over-write this memory, you get seg-fault.

    Try to allocate memory to stole as follows

    unsigned char stole[MAX_SIZE];

    or

    unsigned char *stole = malloc((MAX_SIZE+1) * sizeof(char));
    // +1 for null-terminating
    

    Dynamic String Input

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