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Asked: 2026-05-14T00:18:45+00:00

#include<conio.h> #include<stdio.h> #define abc 7 int main() { int abc=1; printf(%d,abc); getch(); return 0;

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#include<conio.h>
#include<stdio.h>
#define abc 7

int main()
{

int abc=1;

printf("%d",abc);

getch();

return 0;
}

why this program is giving compile time error

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1 Answer

  1. Editorial Team

    You’re assigning 7=1 which is invalid. Since you’ve defined abc to be 7, the preprocessor translates the line:

    int abc=1;

    to:

    int 7=1;

    Which is a syntax error in C (my gcc says syntax error before numeric constant).

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