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Home/ Questions/Q 851669
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T07:27:57+00:00 2026-05-15T07:27:57+00:00

#includeiostream class CMessage { public:int a; CMessage(){} ~CMessage(){} }; void Testing(CMessage *f_pMessage)//l_pMessage is output

  • 0
#include"iostream"
class CMessage
{
public:int a;
       CMessage(){}
       ~CMessage(){}
};
void Testing(CMessage *f_pMessage)//l_pMessage is output parameter
{
    f_pMessage = new CMessage();
    f_pMessage->a = 1;
}
int main()
{
    CMessage *l_pMessage =NULL;
    Testing(l_pMessage);
    std::cout<<l_pMessage->a;//getting l_pMessage = NULL;
    return 0;
}

When I called testing then inside testing f_pMessage is getting initialized but as soon as
i after excuting testing function it should be store in l_Pmessage but it is showing NULL.confussed…..

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  1. Editorial Team
    Editorial Team
    2026-05-15T07:27:58+00:00Added an answer on May 15, 2026 at 7:27 am

    Passing by pointer only allows you to modify what is being pointed at. The pointer itself is still being passed by value.

    Since you want to change a pointer, you can either pass a pointer to a pointer or take the pointer by reference:

    void Testing(CMessage *&f_pMessage)//l_pMessage is output parameter
    {
        f_pMessage = new CMessage();
        f_pMessage->a = 1;
    }
    
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