Question

#include<iostream>
#include<string>
using namespace std;
int main(void) {

    struct STRCT {
        int num;
        string str1,
               arrStr1[],
               str2,
               arrStr2[];
    };

    int a;
    string b[2],
           c[3],
           d,
           e;

    a = 10;

    b[0] = "hello";
    b[1] = "world";

    c[0] = "stack";
    c[1] = "over";
    c[2] = "flow";

    d = "random";
    e = "text";

    //how do i intialize the arrays (arrStr1[] and arrStr2[]) in aStruct along with the rest of items?
    //is it like this?

    //i want aStruct[] to be an array and i want its size to be declared from the start to later be filled with vals

    STRCT aStruct[2];

    //then later in the program i want to assign aStruct[] vals

    aStruct[0] = {a,      //int
                  d,      //string
                  {b},    //string[]
                  e,      //string
                  {c}};   //string[]
}

so basically i want to make a struct array with arrays inside then get the proper vals and then assign the proper vals to the arrays inside the struct array. thank you very much in advance for the help

Answer 1

In C++ this is illegal

string arr[2] = {"This","is"};
string arr1[2];

arr1 = arr;

There is nothing like “copy an entire array into another array”. The array elements must be copied individually.

Second you cant declare arrays of unknown size

You can modify your struct declaration by declaring string array of fixed size and do this

for(int i =0; i< 2; i++)
{

   aStruct[i].num = a;
   aStruct[i].str1= d;

   for(int j=0;j<2;j++)
   {
     arrStr1[i] = b[i];
   }

   aStruct[i].str2= e;

   for(int k=0;k<3;k++)
   {
     arrStr2[i] = c[i];
   }
}

I suggest instead of string arrStr1[] ,string arrStr2[] , b[2] and c[2] make use of std::vector. That will help you in avoid hard coding the conditions in for loop.